Write a query to list all customers who have not placed any order in the last 90 days.
-
SQL
- Write a SQL query to find the second highest salary from an Employees table without using LIMIT or TOP.
- Write a query to find all customers who placed orders in every month of 2025.
- Write a query to identify duplicate rows in a Transactions table based on customer_id, amount, and date.
- Write a query using GROUP BY and HAVING to find departments with more than 10 employees earning above the department average salary.
- Write a query to return the top 3 selling products per category using a subquery (no window functions allowed).
- Write a query to calculate the running total of daily revenue for a store using a self-join.
- Write a query to find the average order value per customer segment, excluding cancelled orders.
- Write a query to find employees who earn more than their direct manager, using a self-join on an Employees table.
- Write a query to list all customers who have not placed any order in the last 90 days.
- Write a query to compute the percentage of total revenue contributed by each product category.
- Write a query to find the first purchase date and last purchase date for every customer.
- Write a query to find the three most recent orders for each customer.
- Write a query that returns customers whose total spend is above the 90th percentile of all customers.
- Write a query to find customers who bought Product A but never bought Product B.
- Write a query to count how many orders each customer placed and rank customers by order count within their city.
- Write a query to identify the busiest hour of the day for support ticket creation using a Tickets table.
- Write a query to find the top 5 referral sources by conversion rate from a Signups table.
- Write a query using EXISTS to find suppliers who have never had a late delivery.
- Write a query to detect gaps in a sequential invoice_number column.
- Write a query to find all products whose price increased in the last price update compared to the previous one.
- Write a query to calculate month-over-month growth rate in active users from a DailyActiveUsers table.
- Write a query to return the department with the highest average tenure of employees.
- Write a query to find all orders placed on weekends versus weekdays and compare average order value.
- Write a query to find customers who upgraded their subscription plan more than once in the last year.
- Write a query to return the top 10% of sales reps by revenue generated in Q1.
- Write a query using a CTE to calculate a 7-day moving average of website visits.
- Write a query to find all patients who missed at least two scheduled appointments in the past year.
- Write a query to identify employees who have never taken a single day of leave in the last two years.
- Write a query to compute year-over-year revenue comparison for each region using self-joins.
- Write a query to find the longest streak of consecutive days a user logged into an app.
- Write a query to identify vendors whose invoice amounts differ by more than 15% from their historical average.
- Write a query to find all students who scored above the class average in more than 3 subjects.
- Write a query to detect accounts with more than 5 failed login attempts within a 10-minute window.
- Write a query to find the second most frequently ordered item for each customer.
- Write a query to identify products frequently bought together, based on an OrderItems table.
- Write a query to find the average time between a support ticket being opened and first responded to, grouped by priority.
- Write a query to find the top-selling product in each store location for the current quarter.
- Write a query to list all foreign keys referencing a given table in a schema (engine-specific system tables allowed).
- Write a query to compute the cumulative distinct count of new customers acquired each month.
Answer
Use a LEFT JOIN (or NOT EXISTS) to find customers with no matching order in the last 90 days.
Solution
SELECT c.customer_id, c.name
FROM Customers c
LEFT JOIN Orders o
ON o.customer_id = c.customer_id AND o.order_date >= CURRENT_DATE - INTERVAL '90 days'
WHERE o.order_id IS NULL;Step by Step
- The join condition includes both the customer match and the 90-day date filter - deliberately placed in the
ONclause, notWHERE. - For customers with a recent order, the join succeeds and
o.order_idis populated. - For customers with no order in that window, the left join produces a row with all
Orderscolumns asNULL. WHERE o.order_id IS NULLkeeps exactly those customers - the ones with no matching recent order.
Alternative Method: NOT EXISTS
SELECT c.customer_id, c.name
FROM Customers c
WHERE NOT EXISTS (
SELECT 1 FROM Orders o
WHERE o.customer_id = c.customer_id AND o.order_date >= CURRENT_DATE - INTERVAL '90 days'
);NOT EXISTS often communicates intent more clearly ("no such order exists") and can perform better than a LEFT JOIN on some engines, since it can stop searching the instant one matching row is found.
Key Exam Traps
- Date filter placement is the critical trap: Putting the 90-day condition in
WHEREinstead of the join'sONclause silently turns theLEFT JOINinto an inner join - becauseWHEREfilters out theNULLrows a left join is specifically meant to preserve. This is the single most common mistake in this exact pattern. - Customers who never ordered at all: They also correctly appear in the result, since they have zero matching order rows - worth confirming whether "no order in 90 days" is meant to include never-ordered customers or only previously-active ones.